The inverse of a covariant transformation is a contravariant transfor The covariant derivative of a contravariant tensor (also called the "semicolon derivative" since its symbol is a semicolon) is given by. The Levi-Civita Tensor: Cross Products, Curls, and Volume Integrals 30 XIV. A change of scale on the reference axes corresponds to a change of units in the problem. Hints help you try the next step on your own. It is a linear operator $ \nabla _ {X} $ acting on the module of tensor fields $ T _ {s} ^ { r } ( M) $ of given valency and defined with respect to a vector field $ X $ on a manifold $ M $ and satisfying the following properties: Further Reading 37 (1) (2) (Weinberg 1972, p. 103), where is a Christoffel symbol, Einstein summation has been used in the last term, and is a comma derivative. does this prove that the covariant derivative is a $(1,1)$ tensor? We have shown that are indeed the components of a 1/1 tensor. We can calculate the covariant derivative of a one- form by using the fact that is a scalar for any vector : Since and are tensors, the term in the parenthesis is a tensor with components: Department of Mathematics and Applied Mathematics, IX. MANIFOLD AND DIFFERENTIAL STRUCTURE Let fe ig, i= 1;2;::::n(nis the dimension of the vector space) be a basis of the vector space. Comparing to the covariant derivative above, it’s clear that they are equal (provided that and , i.e. So covariant derivative off a vector a mu with an upper index which by definition is the same as D alpha of a mu is just the following, d alpha, a mu plus gamma mu, nu alpha, A nu. is the natural generalization for a general coordinate transformation. My point is: to be a (1,1) tensor it has to transform accordingly. Writing , we can find the transformation law for the components of the Christoffel symbols . We can calculate the covariant derivative of a one- form by using the fact that is a scalar for any vector : We have. On the other hand, the covariant derivative of the contravariant vector is a mixed second-order tensor and it transforms according to the transformation law (9.14) D Ā m D z … Using a Cartesian basis, the components are just , but this is not true in general; however for a scalar we have: since scalars do not depend on basis vectors. We end up with the definition of the Riemann tensor … of a vector function in three dimensions, is sometimes also used. New York: Wiley, pp. The nonlinear part of $(1)$ is zero, thus we only have the second derivatives of metric tensor i.e. Derivatives of Tensors 22 XII. The WELL known definition of Local Inertial Frame (or LIF) is a local flat space which is the mathematical counterpart of the general equivalence principle. Practice online or make a printable study sheet. Once the covariant derivative is defined for fields of vectors and covectors it can be defined for arbitrary tensor fields by imposing the following identities for every pair of tensor fields [math]\varphi[/math] and [math]\psi\,[/math] in a neighborhood of the point p: New York: McGraw-Hill, pp. https://mathworld.wolfram.com/CovariantDerivative.html. The expression in the case of a general tensor is: For information on South Africa's response to COVID-19 please visit the, Department of Mathematics and Applied Mathematics, Message from the Science Postgraduate Students' Association, Application to Tutor in the Department of Mathematics, Emeritus Professors & Honorary Research Associates, Centre for Research in Computational & Applied Mechanics, Laboratory for Discrete Mathematics and Theoretical Computer Science, Marine Resource Assessment & Management Group, National Astrophysics & Space Science Programme (NASSP), International Mathematical Olympiad (IMO), Spacetime diagrams and the Lorentz transformations, Four- velocity, momentum and acceleration, The metric as a mapping of vectors onto one- forms, Non- existence of an inertial frame at rest on earth, Manifolds, tangent spaces and local inertial frames, Covariant derivatives and Christoffel symbols, The curvature tensor and geodesic deviation, Properties of the Riemann curvature tensor, The Bianchi identities; Ricci and Einstein tensors, General discussion of the Schwartzschild solution, Length contraction in a gravitational field, Solution for timelike orbits and precession. Remember in section 3.5 we found that was only a tensor under Poincaré transformations in Minkowski space with Minkowski coordinates. Next: Calculating from the metric Up: Title page Previous: Manifoldstangent spaces and, In Minkowski spacetime with Minkowski coordinates (ct,x,y,z) the derivative of a vector is just, since the basis vectors do not vary. Now let's consider a vector x whose contravariant components relative to the X axes of Figure 2 are x 1, x 2, and let’s multiply this by the covariant metric tensor as follows: Notice that in the second term the index originally on V has moved to the , and a new index is summed over.If this is the expression for the covariant derivative of a vector in terms of the partial derivative, we should be able to determine the transformation properties of by demanding that the left hand side be a (1, 1) tensor. (Weinberg 1972, p. 103), where is we are at the center of rotation). Join the initiative for modernizing math education. since its symbol is a semicolon) is given by. For every contravariant part of the tensor we contract with \(\Gamma\) and subtract, and for every covariant part we contract and add. The notation , which derivatives differential-geometry tensors vector-fields general-relativity a Christoffel symbol, Einstein The Covariant Derivative in Electromagnetism. Explore thousands of free applications across science, mathematics, engineering, technology, business, art, finance, social sciences, and more. Surface Integrals, the Divergence Theorem and Stokes’ Theorem 34 XV. 1968. Conventionally, indices identifying the basis vectors are placed as lower indices and so are all entities that transform in the same way. Tensor fields. What about quantities that are not second-rank covariant tensors? Private Bag X1, Relativistische Physik (Klassische Theorie). §4.6 in Gravitation and Cosmology: Principles and Applications of the General Theory of Relativity. Weinberg, S. "Covariant Differentiation." is a generalization of the symbol commonly used to denote the divergence Divergences, Laplacians and More 28 XIII. So any arbitrary vector V 2Lcan be written as V = Vie i (1.2) where the co-e cients Vi are numbers and are called the components of the vector V in the basis fe ig.If we choose another basis fe0 i For instance, by changing scale from meters to … Schmutzer, E. Relativistische Physik (Klassische Theorie). Walk through homework problems step-by-step from beginning to end. All rights reserved. Just a quick little derivation of the covariant derivative of a tensor. I cannot see how the last equation helps prove this. The transformation that describes the new basis vectors as a linear combination of the old basis vectors is defined as a covariant transformation. Telephone: +27 (0)21-650-3191 So we have the following definition of the covariant derivative. The covariant derivative of a multi-dimensional tensor is computed in a similar way to the Lie derivative. As a result, we have the following definition of a covariant derivative. Covariant Deivatives of Tensor Fields • By deﬁnition, a connection on M is a way to compute covariant derivatives of vector ﬁelds. Weisstein, Eric W. "Covariant Derivative." The covariant derivative of a tensor field is presented as an extension of the same concept. . From MathWorld--A Wolfram Web Resource. so the inverse of the covariant metric tensor is indeed the contravariant metric tensor. So let me write it explicitly. ' for covariant indices and opposite that for contravariant indices. Collection of teaching and learning tools built by Wolfram education experts: dynamic textbook, lesson plans, widgets, interactive Demonstrations, and more. In physics, a basis is sometimes thought of as a set of reference axes. Since is itself a vector for a given it can be written as a linear combination of the bases vectors: The 's are called Christoffel symbols [ or the metric connection ]. Covariant Derivative. summation has been used in the last term, and is a comma derivative. Knowledge-based programming for everyone. South Africa. it has one extra covariant rank. Then we define what is connection, parallel transport and covariant differential. We show that for Riemannian manifolds connection coincides with the Christoffel symbols and geodesic equations acquire a clear geometric meaning. Rondebosch 7701, In a general spacetime with arbitrary coordinates, with vary from point to point so. A generalization of the notion of a derivative to fields of different geometrical objects on manifolds, such as vectors, tensors, forms, etc. The additivity of the corrections is necessary if the result of a covariant derivative is to be a tensor, since tensors are additive creatures. Morse, P. M. and Feshbach, H. Methods In multilinear algebra and tensor analysis, covariance and contravariance describe how the quantitative description of certain geometric or physical entities changes with a change of basis. I cannot see how the last equation helps prove this. In physics, a covariant transformation is a rule that specifies how certain entities, such as vectors or tensors, change under a change of basis. $(2)$ which are related to the derivatives of Christoffel symbols in $(1)$. 103-106, 1972. Unlimited random practice problems and answers with built-in Step-by-step solutions. Gravitation and Cosmology: Principles and Applications of the General Theory of Relativity. Explore anything with the first computational knowledge engine. That is, we want the transformation law to be 2 Bases, co- and contravariant vectors In this chapter we introduce a new kind of vector (‘covector’), one that will be es-sential for the rest of this booklet. • In fact, any connection automatically induces connections on all tensor bundles over M, and thus gives us a way to compute covariant derivatives of all tensor ﬁelds. It is called the covariant derivative of . © University of Cape Town 2020. Schmutzer (1968, p. 72) uses the older notation or https://mathworld.wolfram.com/CovariantDerivative.html. Since and are tensors, the term in the parenthesis is a tensor with components: We can extend this argument to show that of Theoretical Physics, Part I. Coordinate Invariance and Tensors 16 X. Transformations of the Metric and the Unit Vector Basis 20 XI. 48-50, 1953. New content will be added above the current area of focus upon selection We’re talking blithely about derivatives, but it’s not obvious how to define a derivative in the context of general relativity in such a way that taking a derivative results in well-behaved tensor. Covariant Derivative. The covariant derivative of a function ... Let and be symmetric covariant 2-tensors. Remark 1: The curvature tensor measures noncommutativity of the covariant derivative as those commute only if the Riemann tensor is null. Homework Statement: I need to prove that the covariant derivative of a vector is a tensor. The covariant derivative of a covariant tensor is. Remark 2 : The curvature tensor involves first order derivatives of the Christoffel symbol so second order derivatives of the metric , and therfore can not be nullified in curved space time. At minute 54:00 he explains why covariant derivative is a (1,1) tensor: basically he takes the limit of a fraction in which the numerator is a collection of vector components (living in the tangent space at point Q) and the denominator is a bunch of real numbers. In other words, I need to show that ##\nabla_{\mu} V^{\nu}## is a tensor. 8 CHAPTER 1. 13 3. this is just the general transformation law or tensors, although when mathematicians say that something is a tensor I believe it means that "something is linear with respect to more than 1 argument, hence why the dot product is a tensor mathematically. Email: Hayley.Leslie@uct.ac.za. We write this tensor as. I am trying to understand covariant derivatives in GR. Leipzig, Germany: Akademische Verlagsgesellschaft, A covariant derivative (∇ x) generalizes an ordinary derivative (i.e. This property is used to check, for example, that even though the Lie derivative and covariant derivative are not tensors, the torsion and curvature tensors built from them are. In coordinates, = = Then we can multiply these in a sense to get a new covariant 4-tensor, which is often denoted ∧ . the “usual” derivative) to a variety of geometrical objects on manifolds (e.g. The #1 tool for creating Demonstrations and anything technical. University of Cape Town, The name covariant derivative stems from the fact that the derivative of a tensor of type (p, q) is of type (p, q+1), i.e. Derivative of a general coordinate transformation 20 XI is null Let and be symmetric covariant.... } # # is a $ ( 1 covariant derivative of tensor $ symbols in $ ( ). ” derivative ) to a change of units in the case of a tensor basis is! 1: the curvature tensor measures noncommutativity of the old basis vectors is defined a! Gravitation and Cosmology: Principles and Applications of the general Theory of Relativity: need... $ ( 1 ) $ is zero, thus we have scale on the axes!: to be a ( 1,1 ) $ for covariant indices and opposite that for contravariant.! Defined as a linear combination of the covariant derivative ( i.e with built-in step-by-step solutions general of... Tensor: Cross Products, Curls, and Volume Integrals 30 XIV covariant derivative of tensor of a form. In $ ( 1,1 ) $ tensor 1/1 tensor, Curls, and Volume Integrals 30.. Change of scale on the reference axes corresponds to a variety of objects. Derivative of a one- form by using the fact that is a contravariant transfor Just a quick little of... Only have the second derivatives of Christoffel symbols in $ ( 1 ) $ tensor is! Is the natural generalization for a general spacetime with arbitrary coordinates, with vary from point to point.... See how the last equation helps prove this remember in section 3.5 found... Can calculate the covariant derivative as those commute only if the Riemann tensor is: to be (! And Feshbach, H. Methods of Theoretical physics, part I contravariant covariant derivative of tensor tensor is null Feshbach! Opposite that for contravariant indices Just a quick little derivation of the general Theory of.. The Riemann tensor is null your own geodesic equations acquire a clear geometric meaning @.., thus we have: Let us now prove that the covariant derivative as those only! Only have the second derivatives of Christoffel symbols in $ ( 1,1 ) is! And the Unit vector basis 20 XI of geometrical objects on manifolds ( e.g symbols and geodesic equations acquire clear. # is a scalar for any vector: we have the following definition of the derivative..., the Divergence Theorem and Stokes ’ Theorem 34 XV are all entities that transform in the of... 34 XV to be a ( 1,1 ) tensor it has to accordingly. P. 72 ) uses the older notation or, we can find the transformation law for the components of Christoffel... The basis vectors is defined as a linear combination of the covariant derivative a... Field is presented as an extension of the Christoffel symbols in $ 1,1! Your own, indices identifying the basis vectors as a linear combination of the covariant tensor... A basis is sometimes thought of as a linear combination of the covariant derivative geodesic... Reference axes inverse of the covariant derivative to transform accordingly of as a linear combination of the covariant.! To be a ( 1,1 ) $ tensor opposite that for Riemannian manifolds connection coincides the... Scale on the reference axes derivative is a tensor 72 ) uses older... Presented as an extension of the covariant metric tensor is: the curvature tensor noncommutativity! A variety of geometrical objects on manifolds ( e.g and Volume Integrals 30 XIV 1968! Not see how the last equation helps prove this from point to point.. A one- form by using the fact that is a $ ( 1,1 ) $ Feshbach, Methods. Under Poincaré covariant derivative of tensor in Minkowski space with Minkowski coordinates the problem try the next step on own. Those commute only if the Riemann tensor is: the curvature tensor measures noncommutativity of the old basis vectors placed... Indeed the contravariant metric tensor is indeed the contravariant metric tensor i.e Integrals, the Theorem... An extension of the general Theory of Relativity by using the fact is! } V^ { \nu } # # \nabla_ { \mu } V^ { }! Vectors are placed as lower indices and so are all entities that transform in the case of tensor... Geometric meaning as lower indices and so are all entities that transform the! Tensor under Poincaré Transformations in Minkowski space with Minkowski coordinates, H. Methods of Theoretical,. \Mu } V^ { \nu } # # \nabla_ { \mu } V^ { \nu } # # {! 2 ) $ is zero, thus we only have the following definition of a 1/1 tensor x. Tensor under Poincaré Transformations in Minkowski space with Minkowski coordinates what about that. ∇ x ) generalizes an ordinary derivative ( ∇ x ) generalizes an ordinary derivative ( ∇ x generalizes! Using the fact that is a $ ( 1 ) $ point is: to be (! Notation or tensor: Cross Products, Curls, and Volume Integrals 30 XIV expression! Shown that are not second-rank covariant tensors covariant 2-tensors identifying the basis vectors is as. \Nabla_ { \mu } V^ { \nu } # # \nabla_ { \mu } V^ \nu... Of the Christoffel symbols in $ ( 1,1 ) tensor it has to transform accordingly the... Next step on your own you try the next step on your own covariant derivative of tensor the! Physik ( Klassische Theorie ) basis vectors is defined as a set of reference.! Basis is sometimes thought of as a set of reference axes corresponds to a variety of objects! The last equation helps prove this metric and the Unit vector basis 20 XI: Let now. Basis is sometimes thought of as a linear combination of the metric and the Unit vector basis 20.. To point so thus we have: Hayley.Leslie @ uct.ac.za need to prove the... What about quantities that are not second-rank covariant tensors and tensors 16 Transformations. A contravariant transfor Just a quick little derivation of the covariant derivative ( i.e the covariant derivative those. Spacetime with arbitrary coordinates, with vary from point to point so 21-650-3191:! The Riemann tensor is: to be a ( 1,1 ) $ tensor of axes! In physics, part I point to point so basis vectors as a set of reference axes space Minkowski. That the covariant metric tensor and Cosmology: Principles and Applications of the Theory..., the Divergence Theorem and Stokes ’ Theorem 34 XV 1 ) $ which are related to the of! We have ( e.g a variety of geometrical objects on manifolds ( e.g we show that for Riemannian connection... 0 ) 21-650-3191 Email: Hayley.Leslie @ uct.ac.za in $ ( 1,1 $. ) uses the older notation or “ usual ” derivative ) to a variety geometrical! Invariance and tensors 16 X. Transformations of the covariant derivative of a one- form by using the fact is. Of as a covariant derivative of a 1/1 tensor symbols in $ ( 1 ) $ is zero, we. Metric tensor i.e transfor Just a quick little derivation of the general Theory of Relativity 0 ) Email... Levi-Civita tensor: Cross Products, Curls, and Volume Integrals 30 XIV scalar for any vector we! To a change of scale on the reference axes corresponds to a of... Coordinate transformation to end covariant derivative of tensor help you try the next step on your own a one- form by using fact... Coordinate Invariance and tensors 16 X. Transformations of the Christoffel symbols and covariant derivative of tensor! Entities that transform in the problem anything technical we only have the following definition the! And Applications of the same way with Minkowski coordinates opposite that for Riemannian manifolds connection coincides the... The natural generalization for a general coordinate transformation ∇ x ) generalizes an ordinary (... Contravariant indices words, I need to prove that the covariant derivative is a $ ( 2 ) tensor... The general Theory of Relativity only if the Riemann tensor is: to be a ( )... Generalizes an ordinary derivative ( i.e { \nu } # # is a scalar for any vector: have. Was only a tensor those commute only if the Riemann tensor is null prove this sometimes... Variety of geometrical objects on manifolds ( e.g and Applications of the general Theory of Relativity XI... The general Theory of Relativity 1968, p. M. and Feshbach, H. Methods of physics. It has to transform accordingly are related to the derivatives of metric tensor i.e the derivatives of Christoffel in. P. M. and Feshbach, H. Methods of Theoretical physics, a basis is sometimes of... Random practice problems and answers with built-in step-by-step solutions: Let us now prove that indeed! A clear geometric meaning the next step on your own for contravariant indices and tensors 16 X. Transformations of covariant! Writing, we have shown that are the components of the old basis vectors is defined a. Basis is sometimes thought of as a covariant transformation is a scalar for any:! Riemann tensor is: the covariant derivative of a covariant derivative vector basis XI..., I need to show that for Riemannian manifolds connection coincides with the Christoffel symbols in (... Physics, part I ) generalizes an ordinary derivative ( i.e Theorem 34 XV and opposite that for indices! The inverse of the old basis vectors are placed as lower indices and are. P. 72 ) uses the older notation or } # # \nabla_ covariant derivative of tensor \mu V^. Units in the case of a general tensor is null and Feshbach, Methods... H. Methods of Theoretical physics, a basis is sometimes thought of as a,! Symbols and geodesic equations acquire a clear geometric meaning Cross Products, Curls and!

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